The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.

Options

A. `lamda = lamda_2`
B. `lamda_1 = 2 lamda_2`
C. `lamda_1 = (1)/(2) lamda_2`
D. `lamda_1 = 4 lamda_2`

Answer

B

Explanation

(b) `E_1 = (hc)/(lamda_1)` and `E_2 = (hc)/(lamda_2)`
`:. (E_1)/(E_2) = (lamda_2)/(lamda_1)`
`(25)/(50) = (lamda_2)/(lamda_1)`
`:. lamda_1 = 2 lamda_2`.