The correct set of four quantum number for the valence (outermost) electron of radiation `(Z = 37)` is

Options

A. `5, 0, 0, + (1)/(2)`
B. `5, 1, 0, + (1)/(2)`
C. `5, 1, 1, + (1)/(2)`
D. `6, 0, 0, + (1)/(2)`

Answer

A

Explanation

(a) The electronic configuration of `._37 Rb` is : `1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6 3 d^10, 4 s^2 4 p^6, 5 s^1`
`n = 5, 1 = 0, m = 0, s = + (1)/(2)` or `- (1)/(2)`.