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The angular momentum of p electron is...

The angular momentum of p electron is

A

`sqrt(6). (h)/(2 pi)`

B

`sqrt(3) (h)/(2 pi)`

C

`sqrt((3)/(2)) (h)/(pi)`

D

`(h)/(sqrt(4) pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Orbital angular momentum `= sqrt(l(l + 1)) xx (h)/(2 pi)`
For `p-"electron" (l = 1)`
=`sqrt(1(l + 1)) xx (h)/(2 pi) = sqrt(2) xx (h)/(2 pi) = (h)/(sqrt(2) pi)`.
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