Number of protons, neutrons and electrons in the element `""_89^231 Y` is.

Options

A. `89, 231, 89`
B. `89, 89, 242`
C. `89, 142, 89`
D. `89, 71, 89`

Answer

C

Explanation

( c) In `Xe_(89)^(231)`, number of protons and electrons is `89` and no. of neutrons `= A - Z = 231 - 89 = 142`.