The uncertainty in momentum of an electron is `1 xx 10^-5 kg - m//s`. The uncertainty in its position will be `(h = 6.62 xx 10^-34 kg = m^2//s)`.

Options

A. `1.05 xx 10^-28 m`
B. `1.05 xx 10^-26 m`
C. `5.27 xx 10^-30 m`
D. `5.25 xx 10^-28 m`

Answer

C

Explanation

( c) We know that `Delta x xx Delta p = (h)/(4 pi)`
`Delta x = (h)/(Delta p xx 4 pi) = (6.62 xx 10^-34)/(1 xx 10^-5 xx4 xx 3.14)`
=`5.27 xx 10^-30 m`.