How many chlorine atoms can you ionize in the process `Cl rarr Cl^+ + e`, by the energy liberated from the following process ?
`Cl + e^- rarr Cl^(-) for 6 xx 10^23 "atoms"`
Given electron affinity ofm `Cl = 3.61 eV`, and `I P` of `Cl = 17.422 eV`.

Options

A. `1.24 xx 10^23 "atoms"`
B. `9.82 xx 10^20 "atoms"`
C. `2.02 xx 10^15 "atoms"`
D. none of these

Answer

A

Explanation

(a) Energy released in conversion of `6 xx 10^23 "atoms"` os `Cl^(-) ions`
=`6 xx 10^23 xx "electron affinity"`,
=`6 xx 10^23 xx 3.61`
=`2.166 xx 10^24 eV`
Let `x Cl` atoms are converted to `Cl^+` ion
Energy absorbed `= x xx "ionization energy"`
`x xx 17.422 = 2.166 xx 10^24`
`x = 1.243 xx 10^23 "atoms"`.