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X mL of H(2) gas effuses through a hole ...

`X mL` of `H_(2)` gas effuses through a hole in a container in `5 s`. The time taken for the effusion of the same volume of the gas specified below, under identical conditions, is

A

`10 secs: He`

B

`20 secs:O_(2)`

C

`25 secs: CO`

D

`55 secs: CO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`((V_(1))/(t_(1)))/(V_(2)/t_(2))=(M_(2))/(M_(1))` or `(t_(2))/(5)=sqrt((M_(2))/(2))`
or `(t_(2)^(2))/(M_(2))=(25)/(2)=((20)^(2))/(32)`
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