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Equal moles of CO, B(2)H(6), H(2) and CH...

Equal moles of `CO, B_(2)H_(6), H_(2)` and `CH_(4)` are placed in a container. If a hole was made in container after `5 "minute"`, partial pressure of gases in container would be
(Atomic weights of `C,O,B` and `H` are `12, 16, 11, 1` respectively)

A

`P_(CO)gt P_(B_(2)H_(6))gtP_(H_(2))gt P_(CH_(4))`

B

`P_(CO)= P_(B_(2)H_(6)) gt P_(CH_(4)) gt P_(H_(2))`

C

`P_(CO) gt P_(B_(2)H_(6))=P_(H_(2)) gt P_(CH_(4))`

D

`P_(B_(2)H_(6)) gt P_(H_(2))gt P_(CH_(4))gt P_(CO)`

Text Solution

Verified by Experts

The correct Answer is:
B
`CO` and `B_(2)H_(6)` have same molecular mass. The diffusion of lighter gas will be more. Thus mole coming out from container will show
`H_(2) gt CH_(4) gt CO= B_(2)H_(6)`
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