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Pressure exerted by 1 mole of methane, i...

Pressure exerted by `1` mole of methane, in a `0.25` litre container at `300K` using van der Waals' equation (given `a= 2.253 atm L^(2) mol^(-2), b= 0.0428L mol^(-))` is

A

`82.82 atm`

B

`152.51 atm`

C

`190.52 atm`

D

`70.52 atm`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P+(n^(2)a)/(V^(2))) (V-nb)=nRT`
`(P+(2.253)/(0.25xx0.25))(0.25-0.0428)=0.0821xx300`
or `(P+36.048)(0.2072)= 24.63`
`implies P+ 36.075= 118.87implies P= 82.82 atm`
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