Weight of `112 ml` of oxygen at `NTP` on liquefaction would be

Options

A. `0.32 g`
B. `0.64 g`
C. `0.16 g`
D. `0.96 g`

Explanation

To find the weight of 112 ml of oxygen at NTP (Normal Temperature and Pressure) on liquefaction, we can follow these steps:

### Step 1: Understand the relationship between volume and mass at NTP
At NTP, 22,400 ml of oxygen gas has a mass of 32 g. This means that we can calculate the mass of oxygen per ml.

### Step 2: Calculate the mass of 1 ml of oxygen
We can find the mass of 1 ml of oxygen using the following formula:
\[ \text{Mass of 1 ml of O}_2 = \frac{32 \text{ g}}{22,400 \text{ ml}} \]
Calculating this gives:
\[ \text{Mass of 1 ml of O}_2 = \frac{32}{22,400} \text{ g} \approx 0.00142857 \text{ g} \]

### Step 3: Calculate the mass of 112 ml of oxygen
Now, we can calculate the mass of 112 ml of oxygen using the mass of 1 ml:
\[ \text{Mass of 112 ml of O}_2 = 112 \text{ ml} \times \frac{32 \text{ g}}{22,400 \text{ ml}} \]
This simplifies to:
\[ \text{Mass of 112 ml of O}_2 = \frac{32 \times 112}{22,400} \text{ g} \]

### Step 4: Perform the calculation
Now we can perform the calculation:
\[ \text{Mass of 112 ml of O}_2 = \frac{3584}{22,400} \text{ g} \approx 0.16 \text{ g} \]

### Conclusion
Thus, the weight of 112 ml of oxygen at NTP on liquefaction is approximately **0.16 g**.