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Assertion: Andrews worked on a temporary...

Assertion: Andrews worked on a temporary gas (so called at that time) and derived the condition to liquefy the permanent gases (so called at that time).
Reason: Andrews studied isotherms of `CO_(2)` and obtained the required conditions of liquefaction of gas as `T gas lt Tc` (critical temperature).

A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

B

If both assertion and reason are true but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

Text Solution

Verified by Experts

The correct Answer is:
A

Andrews studied isotherms of `CO_(2)` and found that even `CO_(2)` ( the so called temporary gas at that time) cannot be liquefied above `31.10^(@)C`, the critical temperature of `CO_(2)`, although pressure may be increased manifolds.
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The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) Gas A and can be liquefied at room temperature by applying pressure but gas B cannot. This reflects:

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) {:("Gases",A,B,C,D,),(P_(c) (atm),2.2,14,35,45,),(T_(c) (K),5.1,33,127,140,):} Which of the above gases cannot be liquefied at 100 K and 50 atm ?

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) The values of criticla volumes of four gases A, B, C and D are 0.025 L, 0.312 L, 0.245 L and 0.432 L respectively. The gas with larger diameter will be :

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