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For the reaction, X(2)O(4)(l)rarr2XO(2...

For the reaction,
`X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal` ,
`DeltaS=20cal//K` at `300K` . Hence `DeltaG` is

A

`2.7Kcal`

B

`-2.7Kcal`

C

`9.3Kcal`

D

`-9.3Kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
From `DeltaH=DeltaE+DeltanRT`
`DeltaH=2.1+2xx(2xx10^(-3))xx300`
`=3.3`
now from `DeltaG=DeltaH-TDeltaS`
`=3.3-300xx(20xx10^(-3))`
`=-2.7Kcal`
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