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For the reaction A(g)+2B(g)rarr2C(g)+3...

For the reaction
`A(g)+2B(g)rarr2C(g)+3D(g)`,
the value of `DeltaH` at `27^(@)C` is `19.0 kcal`. The value of `DeltaE` for the reaction would be
`(R=2.0 cal H^(-1)mol^(-1))`

A

`20.8Kcal`

B

`19.8Kcal`

C

`18.8Kcal`

D

`17.8Kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H = Delta E + Delta n_(g) RT`
`19 = Delta E + ((2xx2xx300)/(1000))`kcal
`19 = Delta E + 1.2`
`Delta E = 19 - 1.2 "kcal" = 17.8 "kcal"`
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