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For the reaction N(2)(g) + 3H(2)(g) hA...

For the reaction
`N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?`

A

`DeltaE+2RT`

B

`DeltaE-2RT`

C

`DeltaE+RT`

D

`DeltaE-RT`

Text Solution

Verified by Experts

The correct Answer is:
D

`Delta H = Delta E + Delta n_(g) RT`
`Delta n_(g) = 2 - u = -2`
So, `Delta H = Delta E + (-2RT)`
`= Delta E - 2RT`
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