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The value of DeltaH(O-H) is 109Kcal//mol...

The value of `DeltaH_(O-H)` is `109Kcal//mol` . The enthalpy of formation of 1 mole of water in gaseous state will be

A

`109xx2KJmol^(-1)`

B

`109KJmol^(-1)`

C

data is not sufficient to predict it

D

`109xx4Kcalmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Formation of water does not merely require the formation of two `O-H` bonds but also require the dissociation of `1mol` of `H_(2)` and `(1)/(2)mol` of `O_(2)`
`H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(g)`
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