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What percentage T(1) is of T(2) for a 10...

What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine? `T_(1)` is the temperature of sink and `T_(2)` is the temperature of heat reservoir.

A

`T_(1)=90%` of `T_(2)`

B

`T_(1)=T_(2)`

C

`T_(2)=90%` of `T_(1)`

D

`T_(1)=50%` of `T_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Efficiency, `eta=(T_(2)-T_(1))/(T_(2)=1-(T_(1))/(T_(2))=0.1`
or `T_(1)=0.9T_(2)`
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