Standard enthalpy and standard entropy change for the oxidation of `NH_(3)` at `298K` are `-382.64KJ mol^(-1)` and `145.6Jmol^(-1)` respectively. Standard free energy change for the same reaction at `298K` is

Options

A. `-221.1KJmol^(-1)`
B. `-339.3KJmol^(-1)`
C. `-439.3KJmol^(-1)`
D. `-523.2KJmol^(-1)`

Answer

A

Explanation

`DeltaH^(@)=-382.64KJmol^(-1)`
Given that, `DeltaS^(@)=-145.6JK^(-1)mol^(-1)`
`=-145.6xx10^(-3)KJK^(-1)`
or `DeltaG^(@)=-382.64-(298xx1-145.6xx10^(3))`
`=-339.3KJmol^(-1)` .