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The enthalpy and entropy change for the ...

The enthalpy and entropy change for the reaction,
`Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)`
are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperation at which the raction will be in equilibrium is:

A

`450K`

B

`300K`

C

`285.7K`

D

`272K`

Text Solution

Verified by Experts

The correct Answer is:
D

At equilibrium, Gibbs's free energy change `(DeltaG)` is equal to zero
`DeltaG=DeltaH-TDeltaS`
`0=30xx10^(3)(Jmol^(-1))-Txx(105)KJ^(-1)mol^(-1)`
`:. T=(30xx10^(3)K)/(105)=285.7K`
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