One mole of an ideal gas is allowed to expand reversible and adiabatically from a temperatureof`27^(@)C)`if the work done during the process is`3`kJ,the final temperature will be equal to`(C_(v)=20JK^(-1))`

Options

A. `150K`
B. `100K`
C. `26.85^(@)C`
D. `295K`

Answer

A

Explanation

We know that work done, `W=C_(v)(T_(1)-T_(2))`
`3xx1000=20(300-T_(2)), :. 3000=6000-20T_(2)`
`:. T_(2)=(3000)/(20)=150K`