In an isobaric process, the ratio of heat supplied to the system `(dQ)` and work done by the system `(dW)` for diatomic gas is

Options

A. `1:1`
B. `7:2`
C. `7:5`
D. `5:7`

Answer

B

Explanation

`-(dQ)/(dW)=(dQ)/(dQ-dE),dE=dW+dQ,-dW`
`=dQ-dWE`
`=(nc_(p)dT)/(nc_(p)dT-nc_(v)dT)=(c_(p))/((c_(p)-c_(v))`
`=(7R)/(2R)` {for diatomic of gas `c_(p)=(7R)/(2)`}