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Given the bond energirs N=N,H-H and N-H ...

Given the bond energirs `N=N,H-H` and `N-H` bonds are `945,436` and `391KJmol^(-1)` respectively, the enthalpy of the follwing reactlon `N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)` is

A

`-93KJ`

B

`102KJ`

C

`90KJ`

D

`105KJ`

Text Solution

Verified by Experts

The correct Answer is:
A

Net energy released `=2346-2253=93KJ`
i.e. `DeltaH=-93KJ`
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