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Ionisation energy of A1=5137KJmol^(-1)(D...

Ionisation energy of `A1=5137KJmol^(-1)(DeltaH)` hydration of `Al^(3+)=-4665KJmol^(-1).(DeltaH)_(hydration)` for `Cl^(-)=-381KJmol^(-1)` . Which of the following statement is correct?

A

`AlCl_(3)` would remauin covalent in aqueous solution

B

Only at infinite dilution `AlCl_(3)` undergoes ionisation

C

In aqueous solution `AlCl_(3)` becomes ionic

D

Nonee of these

Text Solution

Verified by Experts

The correct Answer is:
C

If `AlCl_(3)` is present in ionic state in aqueous solution, therefore it has `Al^(3+)` and `3Cl^(-)` inos
Standard heat of hydration of `Al^(3+)` and `3Cl^(-)` inos `=-4665+3xx(-381)Kjmol^(-1)`
`=-5808KJ//mol`
Required energy of ionisation of `Al=5137KJmol^(-1)`
`:.` Hydration energy overcomes ionisation energy
`:. AlCl_(3)` would be ionic in aqueous solution
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Anhydroug A Cl_(3) is covalent . From the data given below Lattice Energy =5137KJ//mol DeltaH hydrogen for Al^(3+)=-4665KJ//mol DeltaH hydration for Cl^(-)=-381KJ//mol Identify the correct statement.

Anhydrous AlCl_(3) is covalent. From the date given below, predict whether it would remain covalent or become ionic in aqueous solution. (Ionisation energy for Al is 1537 kJ mol^(-1) ) Delta_("hydration") for Al^(3+) = - 4665 kJ mol^(-1) Delta_("hydration") for Cl^(Ө) = - 381 kJ mol^-1 .

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