At `0^(@)C` , ice and water are in reuilibrium and `DeltaS` and `DeltaG` for the conversion of ice to liquid water is

Options

A. `0,21.98JK^(-1)mol^(-1)`
B. `-ve` , zero
C. `-ve,21.98JK^(-1)mol^(-1)`
D. Zero, zero

Answer

C

Explanation

Since the given process is in equilibrium, i.e.,
`DeltaG=0`
`DeltaG=DeltaH-TDeltaS`
or, `0=Delta-TDeltaS` or `DeltaH=TDeltaS`
or, `DeltaS=(DeltaH)/(T)=(6)/(273)xx10^(3)JK^(-1)K^(-1)`
`=21.98JK^(-1)mol^(-1)`