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At 700 K, the equilibrium constant K(p) ...

At `700 K`, the equilibrium constant `K_(p)` for the reaction
`2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g)`
is `1.80xx10^(-3) kPa`. What is the numerical value of `K_(c )` in moles per litre for this reaction at the same temperature?

A

`3.09xx10^(-7)` mol-litre

B

`5.07xx10^(-8)` mol-litre

C

`8.18xx10^(-9)` mol-liter

D

`9.24xx10^(-10)` mol-litre

Text Solution

Verified by Experts

The correct Answer is:
A
`2SO_(3)hArr2SO_(2) + O_(2)`
`Delta n = 3 - 2 = + 1, K_(p) = 1.80xx10^(-3)`
`[RT]^(Delta n) = (8.314xx700)^(1)`
`K_(c) = (K_(p))/((RT)^(Delta n)) = (1.8xx10^(-3))/((8.314xx700)^(1))`
`=3.09xx10^(-7)` mole-liter
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A2Z-CHEMICAL EQUILIBRIUM-Section D - Chapter End Test
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  14. The equilibrium constant for a reacton N(2)(g)+O(2)(g)=2NO(g) is 4xx...

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  17. If CuSO(4).5H(2)O((s))hArrCuSO(4).3H(2)O((s)) + 2H(2)O((l)) K(p) = 1.0...

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  18. In the system, LaCI(3(s)) + H(2)O(g) + heat rarr LaCIO(s) + 2HCI(g) , ...

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  19. The equilibrium constant for the reaction N(2)(g)+O(2)(g) hArr 2NO(g) ...

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  20. For the decomposition reaction: NH(2)COONH(4(s))hArr2NH(3(g))+CO(2(g...

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