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For the reaction H(2)(g) + I(2)(g)hArr2H...

For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` at 721 K the value of equilibrium constant `(K_(c))` is 50. When the equilibrium concentration of both is `0.5` M, the value of `K_(p)` under the same condtions will be

A

`0.002`

B

`0.2`

C

`50.0`

D

`50//RT`

Text Solution

Verified by Experts

The correct Answer is:
C
For the reaction `H_(2) + I_(2)hArr 2HI`
`Delta n = 0`
So `K_(p) = K_(c) :. 50.0`
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