Molar concentration of 96 g of `O_(2)` contained in a 2 L vessel is:

Options

A. `16 mol//L`
B. `1.5 mol//L`
C. `4 mol//L`
D. `24 mol//L`

Explanation

To find the molar concentration of 96 g of \( O_2 \) in a 2 L vessel, we can follow these steps:

### Step 1: Calculate the number of moles of \( O_2 \)
We know that the molar mass of \( O_2 \) (oxygen gas) is 32 g/mol.

To find the number of moles, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Substituting the values:
\[ \text{Number of moles} = \frac{96 \, \text{g}}{32 \, \text{g/mol}} = 3 \, \text{moles} \]

### Step 2: Calculate the molar concentration
Molar concentration (C) is defined as the number of moles of solute per liter of solution. The formula for molar concentration is:
\[ C = \frac{\text{Number of moles}}{\text{Volume (L)}} \]

Substituting the values:
\[ C = \frac{3 \, \text{moles}}{2 \, \text{L}} = 1.5 \, \text{mol/L} \]

### Final Answer
The molar concentration of 96 g of \( O_2 \) contained in a 2 L vessel is \( 1.5 \, \text{mol/L} \).

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