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At a certain temp. 2HI hArrH(2) + I(2) ....

At a certain temp. `2HI hArrH_(2) + I_(2)` . Only `50%` HI is dissociated at equilibrium. The equilibrium constant is

A

`0.25`

B

`1.0`

C

`3.0`

D

`0.50`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(50)underset(100)(2HI)hArrunderset(25)underset(0)(H_(2))+underset(25)underset(0)(I_(2))`
`([H_(2)][I_(2)])/([HI]^(2)) = (25xx25)/(50xx50) = 0.25`
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