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In a chemical equilibrium, the rate cons...

In a chemical equilibrium, the rate constant for the backward reaction is `7.5xx10^(-4)` and the equilibrium constant is `1.5` the rate constant for the forward reaction is:

A

`5xx10^(-4)`

B

`2xx10^(-3)`

C

`1.125xx10^(-3)`

D

`9.0xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`K_(c) = (K_(f))/(K_(b))`
`K_(f) = K_(c)xxK_(b) = 1.5xx7.5xx10^(-4) = 1.125xx10^(-3)`
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