For the reaction `PCI_(3)(g) + CI_(2)(g)hArrPCI_(5)(g)`, the value of `K_(p)` at `250^(@)`C is `0.61` `atm^(-1)`. The value of `K_(c)` at this temperature will be

Options

A. 15 `(mol//I)^(-1)`
B. 26 `(mol//I)^(-1)`
C. 35 `(mol//I)^(-1)`
D. 52 `(mol//I)^(-1)`

Answer

B

Explanation

`PCI_(3)(g) + CI_(2)(g)hArrPCI_(5)(g)`
`Delta n = -1, K_(p) = 0.61 atm^(-1)`
`K_(C) = K_(p)(RT)^(-Delta n)`
`= 0.61 (0.0821xx523)^(1) = 26 mol//L`