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4 moles of A are mixed with 4 moles of B...

`4` moles of A are mixed with `4` moles of B, when `2` moles of C are formed at equilibrium according to the reaction `A+B hArr C+D`.
The value of equilibrium constant is

A

`(1)/(4)`

B

`(1)/(2)`

C

`1`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C

`{:(,,A,+,B,hArr,C,+,D),("Initial conc.",,4,,4,,0,,0),("After T time conc.",,(4-2),,(4-2),,2,,2):}`
Equilibrium constant `= ([C][D])/([A][B]) = (2xx2)/(2xx2) = 1`
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