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2 moles of PCI(5) was heated in a closed...

2 moles of `PCI_(5)` was heated in a closed vessel of 2 litre capacity. At equilibrium, `40%` of `PCI_(5)` is dissociated it `PCI_(3)` and `CI_(2)`. The value of equilibrium constant is

A

`0.266`

B

`0.53`

C

`2.66`

D

`5.3`

Text Solution

Verified by Experts

The correct Answer is:
A

`underset2(PCl_(5))harrunderset0(PCl_(3))+underset0(Cl_(2))`
`(2xx60)/(100)` `(2xx40)/(100)` `(2xx40)/(100)`
Volume of container = 2 L
`K_(c) = ((2xx40)/(100xx2)xx(2xx40)/(100xx2))/((2xx60)/(100xx2)) = 0.266`
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