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Ammonia gas at 15 atm is introduced in a...

Ammonia gas at 15 atm is introduced in a rigid vessel at 300 K. At equilibrium the total pressure of the vessel is found to be 40.11 atm at `300^@C`.The degree of dissociation of `NH_3` will be :

A

`0.6`

B

`0.4`

C

unpredictable

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`2NH_(3)hArrN_(2) + 3H_(2)`
`T = 300K` 15 atm
`T = 573 K` `(15)/(300) (573)` atm
`(15)/(300) (573)` `[1 + alpha) = 40.11`
`implies` `alpha = 0.4`
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A2Z-CHEMICAL EQUILIBRIUM-Application Of Equllibrium Constant (K)
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