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In the reaction C(s)+CO(2)(g) hArr 2CO(g...

In the reaction `C(s)+CO_(2)(g) hArr 2CO(g)`, the equilibrium pressure is `12` atm. If `50%` of `CO_(2)` reacts, calculate `K_(p)`.

A

12 atm

B

16 atm

C

20 atm

D

24 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`C(s) + CO_(2)(g)hArr2CO(g)`
`P-P//2` `P= (3P)/(2) =12`
so, `K_(p) =(P^(2))/((P//2)) = 2p=2xx8 =16` atm
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