Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, `PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g))` If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PC1_(5)` is x, the partial pressure of `PC1_(3)` will be:

Options

A. `((x)/(1 - x))P`
B. `((x)/(x + 1))P`
C. `((2x)/(1 - x))P`
D. `((x)/(x - 1))P`

Answer

B

Explanation

`{:(PCl_(5(g)),hArr,PCl_(3(g)),+,Cl_(2(g))),(1,,0,,0),(1-x,,x,,x):}`
Also `P'_(PC1_(3)) = (P_(eq).x)/((1+x))`