Consider the heterogeneous equilibrium in a closed container `NH_(4)HS (s)hArrNH_(3) (g) + H_(2)S(g)` If more `NH_(4)Hs` is added to the equilibrium

Options

A. Partial pressure of `NH_(3)` increases
B. Partial pressure of `H_(2)S` increases
C. Total pressure in the container increases
D. No effect on partial pressure of `NH_(3)` and `H_(2)S`

Answer

D

Explanation

`NH_(4)HS (s)hArrNH_(3)(g) + H_(2)S(g)`
`K_(p)= NH_(3)(g)xxH_(2)S(g)`
Partial pressure of `NH_(3)` and `H_(2)O` do not affect `NH_(4)HS(s)` because `NH_(4)HS(s)` is solid for solid active mass unity.