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At room temperature, the equilibrium con...

At room temperature, the equilibrium constant for the reaction P + Q `hArr` R + S was calculated to be `4.32` . At `425^(@)C` the equilibrium constant became `1.24xx10^(-2)` . This indicates that the reaction

A

is exothermic

B

is endothermic

C

is difficult to predict

D

no relation between `Delta H` and K

Text Solution

Verified by Experts

The correct Answer is:
A
At room temperature, `K = 4.32` and at `425^(@)C`, equilibrium constant becomes `1.24xx10^(-2)` i.e., it is decreases `alpha` with increase in temerature. So, it is exothermic reaction.
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A2Z-CHEMICAL EQUILIBRIUM-Le - Chatellers'S Principle
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