In the reaction `A_(2)(g) + 4B_(2)(g)hArr2AB_(4)(g)`, `Delta H lt 0` . The decomposition of `AB_(4)` (g) will be favoured at

Options

A. Low temperature and high pressure
B. High temperature and low pressure
C. Low temperature and low pressure
D. High temperature and high pressure

Answer

B

Explanation

`2AB_(4)(g)hArrA_(2)(g) + 4B_(2)(g)` , `Delta H = +ve`
As decomposition of `AB_(4)` is endothermic, so reaction proceeds with increase in temperature. Secondly forward reaction proceeds with increase in number of moles of products, so low pressure favours it.