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Ammoina carbonate when heated to 200^(@)...

Ammoina carbonate when heated to `200^(@)C` gives a mixture of `NH_(3)` and `CO_(2)` vapour with a density of `13.0` What is the degree of dissociation of ammonium carbonate ?

A

`3//2`

B

`1//2`

C

2

D

1

Text Solution

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The correct Answer is:
To find the degree of dissociation of ammonium carbonate when heated, we can follow these steps: ### Step 1: Determine the Molecular Weight of Ammonium Carbonate Ammonium carbonate has the formula \( NH_4CO_3 \). To calculate its molecular weight: - Nitrogen (N): 14 g/mol (1 atom) - Hydrogen (H): 1 g/mol (4 atoms, so \( 4 \times 1 = 4 \)) - Carbon (C): 12 g/mol (1 atom) - Oxygen (O): 16 g/mol (3 atoms, so \( 3 \times 16 = 48 \)) Now, summing these up: \[ \text{Molecular weight of } NH_4CO_3 = 14 + 4 + 12 + 48 = 78 \text{ g/mol} \] ### Step 2: Calculate the Initial Vapor Density The vapor density (D) is defined as half the molecular weight: \[ D = \frac{\text{Molecular Weight}}{2} = \frac{78}{2} = 39 \] ### Step 3: Use the Given Final Vapor Density The problem states that the final vapor density after heating is 13. ### Step 4: Set Up the Degree of Dissociation Formula The degree of dissociation (\( \alpha \)) can be calculated using the formula: \[ \alpha = \frac{D - d}{(N - 1) \cdot d} \] Where: - \( D \) = initial vapor density (39) - \( d \) = final vapor density (13) - \( N \) = number of moles of products formed ### Step 5: Determine the Number of Moles (N) When ammonium carbonate decomposes, it produces ammonia (\( NH_3 \)) and carbon dioxide (\( CO_2 \)). The balanced reaction is: \[ NH_4CO_3 \rightarrow 2NH_3 + CO_2 \] From this reaction, we see that 1 mole of ammonium carbonate produces 2 moles of ammonia and 1 mole of carbon dioxide, totaling 3 moles of products. Therefore, \( N = 3 \). ### Step 6: Substitute Values into the Degree of Dissociation Formula Now we can substitute the values into the formula: \[ \alpha = \frac{39 - 13}{(3 - 1) \cdot 13} = \frac{26}{2 \cdot 13} = \frac{26}{26} = 1 \] ### Conclusion The degree of dissociation of ammonium carbonate is \( \alpha = 1 \). ---

To find the degree of dissociation of ammonium carbonate when heated, we can follow these steps: ### Step 1: Determine the Molecular Weight of Ammonium Carbonate Ammonium carbonate has the formula \( NH_4CO_3 \). To calculate its molecular weight: - Nitrogen (N): 14 g/mol (1 atom) - Hydrogen (H): 1 g/mol (4 atoms, so \( 4 \times 1 = 4 \)) - Carbon (C): 12 g/mol (1 atom) - Oxygen (O): 16 g/mol (3 atoms, so \( 3 \times 16 = 48 \)) ...
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