If the concentration of `OH^(-)` ions in the reaction
`Fe(OH)_(3)(s)hArrFe^(3+)(aq.)+3OH^(-)(aq.)`
is decreased by `1//4` times, then the equilibrium concentration of `Fe^(3+)` will increase by

Options

A. 16 times
B. 64 times
C. 4 times
D. 8 times

Answer

B

Explanation

`K_(c) = [Fe^(3+)][OH^(-)]^(3)`
If `[OH^(-)] = (1)/(4)xx[OH^(-)]` initial, then `[Fe^(3+)]`
`=64 [Fe^(3+)]` initial to have `K_(c)`