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The rate constant for forward and backwa...

The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is

A

`4.33`

B

`5.33`

C

`6.33`

D

`7.33`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(f) = 1.1xx10^(-2), K_(b) = 1.5xx10^(-3)`
`K_(c) = (K_(f))/(K_(b)) = (1.1xx10^(-2))/(1.5xx10^(-3)) = 7.33`
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