At 298 K equilibrium constant `K_(1)` and `K_(2)` of following reaction `SO_(2)(g) +1//2 O_(2)(g)hArr SO_(3)(g).....(1)`
`2SO_(3)(g)hArr2SO_(2)(g) + O_(2)(g)` -------(2)
The relation between `K_(1)` and `K_(2)` is

Options

A. `K_(1) = K_(2)`
B. `K_(2) = K_(1)^(2)`
C. `K_(2) = (1)/(K_(1)^(2))`
D. `K_(2) = (1)/(K_(1))`

Answer

C

Explanation

`K_(1) = ([SO_(3)])/([SO_(2)][O_(2)]^(1//2))` and `K_(2) = ([SO_(2)]^(2)[O_(2)])/([SO_(3)]^(2))` , `K_(2) = (1)/(K_(1)^(2))`