In the system `A_((s))hArr2B_((g))+3C_((g))`, if the concentration of `C` at equilibrium is increased by a factor of `2`, it will cause the equilibrium concentration of `B` to change to:

Options

A. Two times of its original value
B. One half of its original value
C. `2sqrt(2)` time of its original value
D. `(1)/(2sqrt(2))` times of its original value

Answer

D

Explanation

`A(s) hArr 2B(g) + 3C(g)` ltbvrgt `K_(C) = [C]^(3) [B]^(2)`
If © becomes twice, then let the concentration of B is B' then
`K_(C) = [2C]^(3) [B']^(2) = [C]^(3) [B]^(2)`
or `[B']^(2) = ([B]^(2))/(8)`
or `[B'] = ([B])/(sqrt(2))`