The partial pressure of `CH_(3)OH_((g))`, `CO_((g))` and `H_(2(g))` in equilibrium mixture for the reaction, `CO_((g))+2H_(2(g))hArrCH_(3)OH_((g))` are `2.0`, `1.0` and `0.1` atm respectively at `427^(@)C`. The value of `K_(P)` for deomposition of `CH_(3)OH` to `CO` and `H_(2)` is:

Options

A. `10^(2)` atm
B. `2xx10^(2)atm^(-1)`
C. `50 atm^(2)`
D. `5xx10^(-3)atm^(2)`

Answer

D

Explanation

`K_(p) = P_(CH_(3)OH)/(P_(H_(2))^(2)xxP_(CO)) = (2)/(1xx(0.1)^(2))= 200`
`K_(p)` for reverse reaction will be
`K_(p)^(1) = (1)/(K_(p)) = (1)/(200) = 5xx10^(-3) atm^(2)`