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Calculate pH of a solution of given mixt...

Calculate `pH` of a solution of given mixture (`0.1 "mol " CH_(3)COOH+0.2 mol CH_(3)COONa`) in `100 ml` of mixture. `K=2xx10^(-5)`.

A

`4.6`

B

`5.6`

C

`6.6`

D

`7.6`

Text Solution

Verified by Experts

The correct Answer is:
A

We have
`pH= -log K_(a)+log``(["Salt"])/([Acid])`
`= -log2xx10^(-5)+log``((0.2xx1000)/(100))/((0.1xx1000)/(1000))=4.6`
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