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10^(-2) mole of NaOH was added to 10 lit...

`10^(-2)` mole of `NaOH` was added to `10 litres` of water. The `pH` will change by

A

`4`

B

`3`

C

`11`

D

`7`

Text Solution

Verified by Experts

The correct Answer is:
A
Old `pH=7`
New `[OH]=10^(-2)(1)/(10)=10^(-3)`
New `pH=11`
Change is `pH=4`
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A2Z-IONIC EQUILIBIUM-Section D - Chapter End Test
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