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For a weak acid HA with dissociation con...

For a weak acid `HA` with dissociation constant `10^(-9)`, `pOH` of its `0.1 M` solution is

A

`9`

B

`3`

C

`11`

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
D
Dissociation constant of `HA=10^(-9)`
`HAhArrH^(+)+A^(-)`
`[H^(+)]=sqrt((K_(a))/(C))=sqrt((10^(-9))/(0.1))` ,`[H^(+)]=10^(-4)`
`:. pH=4`
`:' pH+pOh=14`
`pOH=14-pH=14-4`, `pOH=10`
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