Electronic configuration of `M^(3+)` is `[Ar]3d^(10)4s^(2)`, it belongs to

Options

A. s-block
B. p-block
C. d-block
D. f-block

Answer

B

Explanation

`EC or M^(3+) = [Ar]3d^(10)4s^(2)`
`:. EC of M = [Ar]3d^(10)4s^(2)p^(3)`
The last electron enters in p-subshell hence it belong to p-block .