The order of magnitude of ionic radii of ions `Na^(+),Mh^(2+),Al^(3+)` and `Si^(4+)` is

Options

A. `Na^(+)ltMg^(2+)ltAl^(3+)ltSi^(4+)`
B. `Mg^(2+)gtNa^(+)gtAl^(3+)gtSi^(4+)`
C. `Al^(3+)gtNa^(+)gtSi^(4+)gtMg^(2+)`
D. `Na^(+)gtMg^(2+)gtAl^(3+)gtSi^(4+)`

Answer

D

Explanation

`Na^(+)gtMg^(2+)gtAl^(3+)gtSi^(4+)`. All are isoelectronic but nuclear charge per electron is greatest for `Si^(4+)`. So it has smallest size and nuclear charge for `N^(a+)` is smallest . So it has largest size .