`PbCl_(4)` exists but `PbBr_(4)` and `PbI_(4)` do not because of

Options

A. Inability of bromine and iodine to oxidise `Pb^(2+)` to `Pb^(4+)`
B. `Br^(-)` and `I^(-)` are bigger in size
C. More electropositive character of `Br_(2)` and `I_(2)`
D. Chlorine is a gas

Answer

B

Explanation

Inability of bromine and iodine to oxidise `Pb^(+2)` to `Pb^(+4)`
`Cl_(2)` can oxidise `Pb^(+2)` to `Pb^(+4)`, But `Br_(2)` and `I_(2)` can't oxidise.