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Two identical positive charges are fixed...

Two identical positive charges are fixed on the y-axis, at equal distances from the origin O. A particle with a negative charges starts on the x-axis at a large distance from O. moves along the x-axis passes through O, and moves far away from O on the other side. Its acceleration a is taken as positive along its direction of motion. Plot acceleration a of the particle against its x-coordinate.

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
Since `E_1 =E_2 ` so
`E=2 E_1 cos theta`
` (##NG_PHY_C01_E01_007_S01.png" width="80%">
`E= (2 Kq x) /(x^2 + y^2 )^(3//2)`
`E` will be max when
`(dE)/(dx) = d/(dx) [(2 Kq x)/((x^(2)+y^(2))^(3//2))]`
Gives ` x= y/(sqrt y)`
so acceleation will be max at `x = y/(sqrt 2)`

and zero ` (E=0 )` at ` x =0` .
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